vga_showcursor - Man Page

show / hide mouse cursor


#include <vga.h>

void vga_showcursor(int show);


if show == 0, hides the cursor.

if show == 1, shows the cursor.

if show == 2, hides the cursor only if a software cursor is in use.


The show == 2 case is needed, since drawing over the software cursor is not allowed. This means that when the program needs to draw and can not be sure that the cursor is not overwritten, it needs to hide the cursor before drawing. This might cause the cursor to flicker. If the  cursor is hidden by calling vga_showcursor(2) (instead of vga_showcursor(0) ), then hardware cursor will not flicker.

See Also

svgalib(7), mouse_init(3), vga_selectcursor(3), vga_initcursor(3), vga_setcursorposition(3), vga_setcursorimage(3),


This manual page written by Matan Ziv-Av <>.

Referenced By

vga_initcursor(3), vga_selectcursor(3), vga_setcursorimage(3), vga_setcursorposition(3).

23 June 2001 Svgalib (>= 1.9.6) Svgalib User Manual