seq man page

seq — print a sequence of numbers

TL;DR

seq 10

seq 5 3 20

seq -s " " 5 3 20

Synopsis

seq [OPTION]... LAST
seq [OPTION]... FIRST LAST
seq [OPTION]... FIRST INCREMENT LAST

Description

Print numbers from FIRST to LAST, in steps of INCREMENT.

Mandatory arguments to long options are mandatory for short options too.

-f, --format=FORMAT
use printf style floating-point FORMAT
-s, --separator=STRING
use STRING to separate numbers (default: \n)
-w, --equal-width
equalize width by padding with leading zeroes
--help
display this help and exit
--version
output version information and exit

If FIRST or INCREMENT is omitted, it defaults to 1. That is, an omitted INCREMENT defaults to 1 even when LAST is smaller than FIRST. The sequence of numbers ends when the sum of the current number and INCREMENT would become greater than LAST. FIRST, INCREMENT, and LAST are interpreted as floating point values. INCREMENT is usually positive if FIRST is smaller than LAST, and INCREMENT is usually negative if FIRST is greater than LAST. INCREMENT must not be 0; none of FIRST, INCREMENT and LAST may be NaN. FORMAT must be suitable for printing one argument of type 'double'; it defaults to %.PRECf if FIRST, INCREMENT, and LAST are all fixed point decimal numbers with maximum precision PREC, and to %g otherwise.

Author

Written by Ulrich Drepper.

Reporting Bugs

GNU coreutils online help: <http://www.gnu.org/software/coreutils/>
Report seq translation bugs to <http://translationproject.org/team/>

See Also

Full documentation at: <http://www.gnu.org/software/coreutils/s…>
or available locally via: info '(coreutils) seq invocation'

Referenced By

enum(1).

November 2016 GNU coreutils 8.26 User Commands